About Carbonyl compounds in FSC Chemistry
Carbonyl compounds is one of the 19 main chapters in our Federal Board FSC Chemistry question bank (11th and 12th class), and about 4% of its real questions come from it. Tayyari Karo has 18 real questions on this chapter from 2023 to 2026; 8 are multiple choice and marked instantly, and the rest are short and long questions with a model answer. By difficulty: 9 hard, 8 medium, 1 easy.
Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.
Try 8 real questions
These are real past-paper questions. Think of your answer first, then open the explanation.
2026 Annual · 12th · Carbonyl compounds
Propanone (CH₃-CO-CH₃) gives how many ¹³C NMR signals?
- 4
- 3
- 2
- 1
Show answer and explanation
Answer: C. 2
Propanone has 2 distinct carbon environments: the two equivalent terminal CH₃ carbons (1 signal) and the central carbonyl carbon (1 signal), totaling 2 signals.
2025 1st Annual · 12th · Carbonyl compounds
Which alcohol is NOT the direct product of reaction when Grignard reagent reacts with aldehydes or ketones?
- Propanol
- 2-Methyl-2-Propanol
- Ethanol
- Methanol
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Answer: D. Methanol
A Grignard reagent always adds at least one new carbon to the carbonyl compound, so a one-carbon alcohol (methanol) can never be the product.
2025 1st Annual · 12th · Carbonyl compounds
Which will be least reactive towards nucleophilic addition reactions?
- Acetone
- Propanal
- Formaldehyde
- Acetaldehyde
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Answer: A. Acetone
Ketones like acetone are least reactive toward nucleophilic addition due to greater steric hindrance and electron donation from two alkyl groups.
2025 2nd Annual · 12th · Carbonyl compounds
Which aldehyde will show aldol condensation?
- Ethanal
- Formaldehyde
- Benzaldehyde
- Propanal
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Answer: A. Ethanal
Aldol condensation requires an α-hydrogen; ethanal (CH₃CHO) has α-hydrogens, unlike formaldehyde/benzaldehyde which lack an α-carbon-H.
2024 Annual · 12th · Carbonyl compounds
Which of the following carbonyl compounds is more reactive in a nucleophilic addition reaction?
- Acetone
- Methanal
- Ethanal
- Propanal
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Answer: B. Methanal
Methanal (formaldehyde) has the least steric hindrance and weakest electron donation to the carbonyl carbon, making it the most reactive towards nucleophilic addition.
2023 Annual · 12th · Carbonyl compounds
The homologous series of ketones have general formula:
- CₙH₂ₙO
- CₙH₄O
- CₙH₂ₙ₋₂O
- CₙH₂ₙ₊₁O
Show answer and explanation
Answer: A. CₙH₂ₙO
Ketones (like aldehydes) contain one C=O per molecule with no extra unsaturation, giving the general formula CₙH₂ₙO.
2025 1st Annual · 11th · Carbonyl compounds
Write down the mechanism of base catalysed nucleophilic addition reaction of formaldehyde (HCHO) with HCN.
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Step 1: Base (OH⁻ or CN⁻ from a trace of base) removes a proton from HCN, generating the nucleophilic cyanide ion, CN⁻.
Step 2: CN⁻ attacks the electrophilic carbonyl carbon of HCHO, and the π electrons of C=O shift onto oxygen, forming an alkoxide intermediate: H₂C(O⁻)(CN).
Step 3: The alkoxide ion abstracts a proton from another HCN molecule (or water), giving the final product, glycolonitrile, HOCH₂CN, and regenerating CN⁻ to continue the cycle.
2025 2nd Annual · 12th · Carbonyl compounds
What is aldol condensation? Write its mechanism when two molecules of Acetaldehyde react together to form Crotonaldehyde.
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Aldol condensation is a reaction in which two molecules of an aldehyde (or ketone) possessing α-hydrogens combine under base (or acid) catalysis, first forming a β-hydroxy aldehyde/ketone (the 'aldol'), which then loses a molecule of water (dehydration) to give an α,β-unsaturated carbonyl compound.
Mechanism (base-catalyzed) for 2 CH₃CHO → Crotonaldehyde:
Step 1: Base (OH⁻) removes an α-hydrogen from one acetaldehyde molecule, forming a resonance-stabilized enolate ion: CH₃CHO → ⁻CH₂CHO.
Step 2: This enolate carbanion (nucleophile) attacks the electrophilic carbonyl carbon of a second acetaldehyde molecule, forming an alkoxide intermediate: CH₃-CH(O⁻)-CH₂-CHO. …
The full model answer is in the app.