Which reagent is used for the reduction of Carboxylic acids to Alcohols?
- KMnO₄
- K₂Cr₂O₇
- LiAlH₄
- H₂/Pt
Show answer and explanation
Answer: C. LiAlH₄
LiAlH₄ is a strong enough reducing agent to reduce carboxylic acids all the way to primary alcohols.
Practise 17 real Federal Board questions on Carboxylic acids from 2023 to 2026. See the answer and explanation as soon as you answer.
Carboxylic acids is one of the 19 main chapters in our Federal Board FSC Chemistry question bank (11th and 12th class), and about 3% of its real questions come from it. Tayyari Karo has 17 real questions on this chapter from 2023 to 2026; 6 are multiple choice and marked instantly, and the rest are short and long questions with a model answer. By difficulty: 12 medium, 4 hard, 1 easy.
Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.
These are real past-paper questions. Think of your answer first, then open the explanation.
Which reagent is used for the reduction of Carboxylic acids to Alcohols?
Answer: C. LiAlH₄
LiAlH₄ is a strong enough reducing agent to reduce carboxylic acids all the way to primary alcohols.
Which carboxylic acid derivative is least reactive?
Answer: A. Amide
Amides are the least reactive carboxylic acid derivative toward nucleophilic acyl substitution, due to strong resonance delocalization of the N lone pair into the carbonyl.
The order of acidic strength of alcohols, phenol and carboxylic acids is:
Answer: A. Carboxylic acids > Phenols > Alcohols
Carboxylate ions are best resonance-stabilized, phenoxide ions less so, and alkoxide ions not at all — so acidity order is carboxylic acids > phenols > alcohols.
The reaction CH₃COOH with LiAlH₄ gives:
Answer: B. CH₃CH₂OH
LiAlH₄ reduces carboxylic acids all the way to primary alcohols: CH₃COOH → CH₃CH₂OH.
How many different types of protons are there in Butanoic acid (CH₃CH₂CH₂COOH)?
Answer: C. 4
Butanoic acid has 4 distinct proton environments: the terminal CH₃, the middle CH₂, the CH₂ next to –COOH, and the –COOH proton itself.
Base hydrolysis of esters in knowns as:
Answer: D. Saponification
Alkaline hydrolysis of an ester into an alcohol and a carboxylate salt is called saponification (soap-making reaction).
Compare the acidities of CH₃COOH and CH₂ClCOOH and explain the difference.
CH₂ClCOOH (chloroacetic acid) is more acidic than CH₃COOH (acetic acid). The electronegative chlorine atom exerts an electron-withdrawing inductive (−I) effect, which pulls electron density away from the carboxylate group, stabilizing the conjugate base (CH₂ClCOO⁻) by dispersing its negative charge. This greater stabilization of the conjugate base makes CH₂ClCOOH dissociate more readily (stronger acid) compared to CH₃COOH, where the methyl group's weak +I effect (electron donating) slightly destabilizes the conjugate base instead.
How can acetic acid be prepared by Grignard reagent?
Grignard reagent (CH₃MgBr) reacts with dry ice (solid CO₂) — the carbanion attacks the electrophilic carbon of CO₂ to form a magnesium carboxylate salt: CH₃MgBr + CO₂ → CH₃COOMgBr. This salt is then hydrolyzed with dilute acid (H₃O⁺) to give acetic acid, CH₃COOH.
| Session | Questions |
|---|---|
| 2026 Annual | 2 |
| 2025 1st Annual | 5 |
| 2025 2nd Annual | 3 |
| 2024 Annual | 4 |
| 2023 Annual | 3 |
17 real Federal Board (FBISE) Chemistry questions on Carboxylic acids from 2023 to 2026, for 11th and 12th class. Each one shows the session it came from.
No. We could not find an official FBISE marking scheme for these papers, so the answers and explanations are written by Tayyari Karo for practice. Check anything important with your teacher or textbook.
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