An element in Group I-A forms ions with charge:
- −1
- +1
- +2
- −2
Show answer and explanation
Answer: B. +1
Group I-A (alkali metal) elements lose their single valence electron to form +1 cations.
Practise 31 real Federal Board questions on Periodic Table and Periodicity from 2023 to 2026. See the answer and explanation as soon as you answer.
Periodic Table and Periodicity is one of the 11 main chapters in our Federal Board Matric Chemistry question bank (9th class), and about 9% of its real questions come from it. Tayyari Karo has 31 real questions on this chapter from 2023 to 2026; 14 are multiple choice and marked instantly, and the rest are short and long questions with a model answer. By difficulty: 16 easy, 15 medium.
Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.
These are real past-paper questions. Think of your answer first, then open the explanation.
An element in Group I-A forms ions with charge:
Answer: B. +1
Group I-A (alkali metal) elements lose their single valence electron to form +1 cations.
Which trend is observed down the Group in Group I-A elements?
Answer: D. Density increases
Density generally increases down group I-A (with a slight anomaly at potassium), while reactivity actually increases and melting point decreases down the group.
The elements of ________ have one electron in their outer shell.
Answer: B. Group I
Group I-A (alkali metals) elements have valence configuration ns¹, i.e. one electron in the outer shell.
An element having electronic configuration 1s², 2s², 2p⁵ belongs to:
Answer: A. Group=VII, Period=2
Highest shell n=2 gives period 2; valence electrons 2+5=7 give group VII-A.
Which of the following is least reactive?
Answer: A. Li
Reactivity of alkali metals increases down the group as ionization energy decreases; Li (topmost) is the least reactive.
Which one of the following is the correct order representing oxidizing power of halogens?
Answer: B. F₂ > Cl₂ > Br₂
Oxidizing power of halogens decreases down the group as atomic size increases, so F₂ > Cl₂ > Br₂ > I₂.
Justify the following statements: (a) Fluorine has smaller shielding effect than Chlorine (b) Fluorine has high ionization energy than Chlorine
(a) Fluorine (2,7) has fewer inner electron shells than chlorine (2,8,7); shielding effect increases with the number of inner shells, so with only 1 inner shell, fluorine has a smaller shielding effect than chlorine (which has 2 inner shells).
(b) Because fluorine has a smaller atomic radius and smaller shielding effect, its valence electrons are held more tightly by the nucleus (effective nuclear charge felt is higher), so fluorine has a higher ionization energy than chlorine, which is further down the group with a larger atomic radius.
Briefly describe the following terms along with their trends in groups and periods: (a) Ionization energy (b) Electron affinity
(a) Ionization energy: the minimum energy required to remove the most loosely bound electron from an isolated gaseous atom, forming a cation. Trend down a group: decreases (atomic size increases, outer electrons are farther from the nucleus and more shielded). Trend across a period (left to right): increases (nuclear charge increases, electrons held more tightly).
(b) Electron affinity: the energy released when an isolated gaseous atom gains an electron to form a negative ion (anion). Trend down a group: generally decreases (increasing atomic size reduces attraction for the added electron). …
The full model answer is in the app.
| Session | Questions |
|---|---|
| 2026 Annual | 6 |
| 2025 1st Annual | 5 |
| 2025 2nd Annual | 6 |
| 2024 Annual | 7 |
| 2023 Annual | 7 |
31 real Federal Board (FBISE) Chemistry questions on Periodic Table and Periodicity from 2023 to 2026, for 9th class. Each one shows the session it came from.
No. We could not find an official FBISE marking scheme for these papers, so the answers and explanations are written by Tayyari Karo for practice. Check anything important with your teacher or textbook.
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