If a man applies 50 N of force to lift a load 0.5 m upward then what is the work done?
- 10 J
- 20 J
- 25 J
- 50 J
Show answer and explanation
Answer: C. 25 J
W = F × d = 50 × 0.5 = 25 J.
Matric Physics: Work and Energy, questions with answers
Practise 17 real Federal Board questions on Work and Energy from 2023 to 2026. See the answer and explanation as soon as you answer.
17real questions
6multiple choice
5exam sessions
About Work and Energy in Matric Physics
Work and Energy is one of the 16 main chapters in our Federal Board Matric Physics question bank (9th class), and about 4% of its real questions come from it. Tayyari Karo has 17 real questions on this chapter from 2023 to 2026; 6 are multiple choice and marked instantly, and the rest are short and long questions with a model answer. By difficulty: 11 easy, 6 medium.
Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.
Try 8 real questions
These are real past-paper questions. Think of your answer first, then open the explanation.
In how much time will a 120 W motor lift 200 N weight vertically up to a height of 30 m?
- 50 seconds
- 60 seconds
- 70 seconds
- 80 seconds
Show answer and explanation
Answer: A. 50 seconds
P = W/t ⇒ t = (F × h)/P = (200 × 30)/120 = 50 s.
Work is done only when:
- Force causes displacement
- Force acts only
- Only time is spent
- Motion is zero
Show answer and explanation
Answer: A. Force causes displacement
W = F·d; without displacement in the direction of the force no work is done.
Energy possessed due to motion is called:
- Potential energy
- Nuclear energy
- Thermal energy
- Kinetic energy
Show answer and explanation
Answer: D. Kinetic energy
Kinetic energy = ½mv².
Kilowatt‑hour is the unit of:
- Energy
- Force
- Power
- Torque
Show answer and explanation
Answer: A. Energy
kWh = power × time = energy. 1 kWh = 3.6 × 10⁶ J.
A force of 500 N is applied to move a body through 9 m in 90 s. The power is:
- 5 W
- 45 W
- 50 W
- 500 W
Show answer and explanation
Answer: C. 50 W
P = W/t = (F × d)/t = (500 × 9)/90 = 50 W.
Prove that K.E. = ½mv².
Show model answer
Let a body of mass m moving with velocity v be stopped in distance S by a constant opposing force F, producing retardation a. The kinetic energy equals the work done: K.E. = F × S = maS ... (1)
Third equation of motion (vi = v, vf = 0, acceleration −a): 2(−a)S = 0 − v² ⇒ aS = v²/2 ... (2)
Substituting (2) in (1): K.E. = ½mv²
Prove that 1 kWh = 3.6 MJ.
Show model answer
1 kWh = 1 kW × 1 h = 1000 W × 3600 s
= 1000 J s⁻¹ × 3600 s = 3,600,000 J = 3.6 × 10⁶ J
Since 1 MJ = 10⁶ J, 1 kWh = 3.6 MJ.
Sessions with Work and Energy questions
| Session | Questions |
|---|---|
| 2026 Annual | 4 |
| 2025 1st Annual | 3 |
| 2025 2nd Annual | 3 |
| 2024 Annual | 4 |
| 2023 Annual | 3 |
Common questions
What does the Work and Energy chapter cover on this page?
17 real Federal Board (FBISE) Physics questions on Work and Energy from 2023 to 2026, for 9th class. Each one shows the session it came from.
Are the answers official?
No. We could not find an official FBISE marking scheme for these papers, so the answers and explanations are written by Tayyari Karo for practice. Check anything important with your teacher or textbook.
Is it free?
You can start free with no signup. A small set of papers per subject is free, and Premium unlocks the full question bank.
Other Physics chapters
- Current Electricity 31
- Dynamics 30
- Physical Quantities and Measurement 29
- Kinematics 29
- Properties of Matter 24
- Electromagnetism 24
- Geometrical Optics 22
- Thermal Properties of Matter 21
- Atomic and Nuclear Physics 21
- Sound 21
- Electrostatics 21
- Basic Electronics 20
- Simple Harmonic Motion and Waves 19
- Turning Effect of Forces 18
- Magnetism 17