Period of tan(5x/7) is:
- 5π/7
- 5π
- 7π/5
- 7π
Show answer and explanation
Answer: C. 7π/5
Period of tan(kx)=π/k; k=5/7 ⇒ π/(5/7)=7π/5.
Practise 26 real Federal Board questions on Fundamentals of Trigonometry from 2023 to 2026. See the answer and explanation as soon as you answer.
Fundamentals of Trigonometry is one of the 14 main chapters in our Federal Board FSC Mathematics question bank (11th and 12th class), and about 5% of its real questions come from it. Tayyari Karo has 26 real questions on this chapter from 2023 to 2026; 13 are multiple choice and marked instantly, and the rest are short and long questions with a model answer. By difficulty: 16 easy, 8 medium, 2 hard.
Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.
These are real past-paper questions. Think of your answer first, then open the explanation.
Period of tan(5x/7) is:
Answer: C. 7π/5
Period of tan(kx)=π/k; k=5/7 ⇒ π/(5/7)=7π/5.
Range of a+bsin2θ is:
Answer: A. a±b
sin2θ∈[−1,1] ⇒ range is [a−b, a+b].
The number of solutions of cosx=0.3 in [0,2π) is:
Answer: C. 2
cosx=0.3 has exactly two solutions in one full period.
If tanθ=2, what is the value of Cosθ when θ is in the first quadrant?
Answer: D. 1/√5
tanθ=2 ⇒ opp=2,adj=1,hyp=√5 ⇒ cosθ=1/√5.
The maximum value of 3+4sinθ is:
Answer: C. 7
sinθ max=1 ⇒ 3+4(1)=7.
What is the period of 3Sin(x/5)?
Answer: A. 10π
Period of Sin(kx) is 2π/k. Here k = 1/5, so period = 2π/(1/5) = 10π (the factor 3 does not affect the period).
Find the maximum and minimum values of: y=1/(4+5cos3x)
cos3x∈[−1,1] ⇒ denominator D=4+5cos3x∈[−1,9]
At D=9 (cos3x=1): y=1/9 (smallest positive value)
At D=−1 (cos3x=−1): y=−1 (largest negative value)
y=−1 and y=1/9 are the extreme values reached at the endpoints of the denominator's range (note y is unbounded near D=0, where cos3x=−4/5)
Find the maximum and minimum values of the function f(θ) = 1/(3+5cos(2θ+π))
3+5cos(2θ+π) = 3−5cos2θ; since cos2θ∈[−1,1], denominator D∈[−2,8]
Largest positive D=8 (cos2θ=−1) gives smallest positive f: f=1/8
Most negative D=−2 (cos2θ=1) gives f=−1/2
Maximum value ≈ −1/2 (at D=−2), minimum positive branch value = 1/8 (at D=8) — note f is unbounded near D=0.
| Session | Questions |
|---|---|
| 2026 Annual | 12 |
| 2025 1st Annual | 6 |
| 2025 2nd Annual | 4 |
| 2024 Annual | 2 |
| 2023 Annual | 2 |
26 real Federal Board (FBISE) Mathematics questions on Fundamentals of Trigonometry from 2023 to 2026, for 11th and 12th class. Each one shows the session it came from.
No. We could not find an official FBISE marking scheme for these papers, so the answers and explanations are written by Tayyari Karo for practice. Check anything important with your teacher or textbook.
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