Work out.
(a) 74.6 × 10 − 3.89 × 100
(b) 5 + 3 × 2 − 1
Show model answer
(a) 74.6 × 10 = 746
3.89 × 100 = 389
746 − 389 = 357
(b) Multiply first: 3 × 2 = 6
5 + 6 − 1 = 10
Multiply before you add or subtract (order of operations).
Practise 390 real Mathematics questions from 2021 to 2026. See the correct answer and a clear explanation the moment you answer.
O Level Mathematics (Cambridge (CAIE) 4024) is examined in the May/June and Oct/Nov series. Tayyari Karo has real questions from 2021 to 2026 across Paper 1, Paper 2, covering topics such as Number, Algebra, Geometry, Statistics and Mensuration. The fastest way to improve is to work through real questions and read why each answer is right.
Tayyari Karo collects the real Cambridge (CAIE) Mathematics questions in one place, sorted by paper and topic. They are structured questions, each with a full model answer.
These are real past-paper questions. Think of your answer first, then open the explanation.
Work out.
(a) 74.6 × 10 − 3.89 × 100
(b) 5 + 3 × 2 − 1
(a) 74.6 × 10 = 746
3.89 × 100 = 389
746 − 389 = 357
(b) Multiply first: 3 × 2 = 6
5 + 6 − 1 = 10
Multiply before you add or subtract (order of operations).
Quadrilateral ABCD has AD extended beyond D to a point E.
Angle BCD = 135°, angle BAD = 83° and angle CDE = 122° (the exterior angle at D, between DC and DE).
Angle ABC = x°.
Find the value of x.
Angle CDE is the exterior angle at D, so the interior angle ADC = 180 − 122 = 58°
The interior angles of quadrilateral ABCD sum to 360°:
angle BAD + angle ABC + angle BCD + angle CDA = 360
83 + x + 135 + 58 = 360
276 + x = 360
x = 84
Find the missing interior angle at D from its exterior angle, then use angle sum of a quadrilateral = 360°.
Trapezium ABCD has parallel sides AB = 7 cm and DC = 10 cm. The area of ABCD is 85 cm². The perpendicular height of the trapezium is h cm.
Find the value of h.
Area of trapezium = (1/2)(a + b)h
85 = (1/2)(7 + 10)h
85 = 8.5h
h = 85 ÷ 8.5
h = 10
Use the trapezium area formula and solve for the height.
(a) Simplify 6x + 15 − 2x + 8.
(b) Expand and simplify (x − 5)².
(a) 6x − 2x = 4x
15 + 8 = 23
Answer = 4x + 23
(b) (x − 5)² = (x − 5)(x − 5)
= x² − 5x − 5x + 25
= x² − 10x + 25
Collect like terms; expand a squared bracket by multiplying it out fully.
Number of questions available for each paper.
| Session | Paper 1 | Paper 2 |
|---|---|---|
| May/June 2026 | 24 | 25 |
| May/June 2025 | 18 | 21 |
| Oct/Nov 2025 | 23 | 23 |
| May/June 2024 | 23 | 10 |
| Oct/Nov 2024 | 22 | 11 |
| May/June 2023 | 25 | 9 |
| Oct/Nov 2023 | 23 | 10 |
| May/June 2022 | 22 | 9 |
| Oct/Nov 2022 | 20 | 10 |
| May/June 2021 | 23 | 9 |
| Oct/Nov 2021 | 21 | 9 |
Yes. Every question comes from a real Cambridge (CAIE) Mathematics (4024) paper from 2021 to 2026. Each one shows the year, session and paper it came from.
You can start free with no signup. A small set of papers per subject is free, and Premium unlocks every paper, the full question bank and the paper PDFs.
Yes. Every question gives you the correct answer straight away with a short explanation, so you learn from mistakes instead of just marking them.
Paper 1, Paper 2 across the May/June and Oct/Nov sessions. Structured questions show a full model answer.