Number of ways of arrangements of the letters in the word 'SUNDAY' are:
- 120
- 480
- 600
- 720
Show answer and explanation
Answer: D. 720
6 distinct letters: 6!=720.
FSC Mathematics: Permutation/Combination/Probability, questions with answers
Practise 19 real Federal Board questions on Permutation/Combination/Probability from 2023 to 2026. See the answer and explanation as soon as you answer.
19real questions
9multiple choice
5exam sessions
About Permutation/Combination/Probability in FSC Mathematics
Permutation/Combination/Probability is one of the 14 main chapters in our Federal Board FSC Mathematics question bank (11th class), and about 4% of its real questions come from it. Tayyari Karo has 19 real questions on this chapter from 2023 to 2026; 9 are multiple choice and marked instantly, and the rest are short and long questions with a model answer. By difficulty: 11 easy, 6 medium, 2 hard.
Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.
Try 8 real questions
These are real past-paper questions. Think of your answer first, then open the explanation.
Number of ways to select 8 players from 12 are:
- 495
- 720
- 11885
- 19958
Show answer and explanation
Answer: A. 495
¹²C₈=495.
How many 5-letter words can be formed from the word 'MATHS' without repeating any letter?
- 20
- 60
- 120
- 240
Show answer and explanation
Answer: C. 120
5 distinct letters, all used: 5!=120.
In how many different ways a player can select 6 numbers from a set of 49 numbers, in a lottery?
- ⁴⁹C₆
- 49!/6!
- ⁴⁹P₆
- 6!
Show answer and explanation
Answer: A. ⁴⁹C₆
Order doesn't matter in a lottery draw ⇒ combination ⁴⁹C₆.
If there is an option for 3 Shirts and 4 Trousers then number of outfits is:
- 12
- 10
- 7
- 1
Show answer and explanation
Answer: A. 12
By fundamental counting principle: 3×4=12.
Number of permutations of 5 distinct objects taken 3 at a time is:
- 10
- 20
- 30
- 60
Show answer and explanation
Answer: D. 60
⁵P₃=5×4×3=60.
Find the value of 'n' if ⁿP₄ : ⁿ⁻¹P₃ = 9:1
Show model answer
ⁿP₄/ⁿ⁻¹P₃ = [n!/(n−4)!] / [(n−1)!/(n−4)!] = n!/(n−1)! = n
So n = 9
n = 9
Consider the letters of the word MANGO. a. Find number of ways to arrange all the letters. b. How many of these arrangements begin with M?
Show model answer
a. 5 distinct letters: 5! = 120 arrangements
b. Fix M first, arrange remaining 4 letters: 4! = 24
Sessions with Permutation/Combination/Probability questions
| Session | Questions |
|---|---|
| 2026 Annual | 5 |
| 2025 1st Annual | 4 |
| 2025 2nd Annual | 4 |
| 2024 Annual | 4 |
| 2023 Annual | 2 |
Common questions
What does the Permutation/Combination/Probability chapter cover on this page?
19 real Federal Board (FBISE) Mathematics questions on Permutation/Combination/Probability from 2023 to 2026, for 11th class. Each one shows the session it came from.
Are the answers official?
No. We could not find an official FBISE marking scheme for these papers, so the answers and explanations are written by Tayyari Karo for practice. Check anything important with your teacher or textbook.
Is it free?
You can start free with no signup. A small set of papers per subject is free, and Premium unlocks the full question bank.