Electric field strength is:
- Work done
- Energy
- Force per unit charge
- Charge per force
Show answer and explanation
Answer: C. Force per unit charge
Electric field strength (intensity) is defined as force per unit positive test charge, E = F/q.
Practise 34 real Federal Board questions on Electrostatics from 2023 to 2026. See the answer and explanation as soon as you answer.
Electrostatics is one of the 14 main chapters in our Federal Board FSC Physics question bank (11th and 12th class), and about 7% of its real questions come from it. Tayyari Karo has 34 real questions on this chapter from 2023 to 2026; 14 are multiple choice and marked instantly, and the rest are short and long questions with a model answer. By difficulty: 26 medium, 8 easy.
Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.
These are real past-paper questions. Think of your answer first, then open the explanation.
Electric field strength is:
Answer: C. Force per unit charge
Electric field strength (intensity) is defined as force per unit positive test charge, E = F/q.
Which of the following CANNOT be accelerated using electric field?
Answer: D. Neutron
A neutron carries no electric charge, so an electric field exerts no force on it and cannot accelerate it.
Coulomb force between two electric charges is 120 N. If the distance between the charges is doubled, the coulomb force will be:
Answer: B. 30 N
F ∝ 1/r². Doubling r reduces F to 1/4 of its original value: 120/4 = 30 N.
The electric dipole moment is the product of:
Answer: D. Charge and displacement
Dipole moment p = q×d, the product of one charge and the separation (displacement) between the two charges.
According to Gauss's law, the electric field inside a hollow conductor is:
Answer: B. Zero
There is no enclosed charge inside a hollow conductor, so by Gauss's law the electric field inside is zero.
There are two charges 1 μC and 6 μC. The ratio of forces acting on them will be:
Answer: C. 1:1
By Newton's third law, the force each charge exerts on the other in a mutual electrostatic interaction is equal in magnitude and opposite in direction — ratio 1:1.
Deduce the dimensions of k from Coulomb's law F = kq₁q₂/r².
k = Fr²/(q₁q₂)
[F] = MLT⁻², [r²] = L², [q₁q₂] = A²T² (charge = current × time)
[k] = (MLT⁻²)(L²)/(A²T²)
[k] = ML³T⁻⁴A⁻²
An object having a net charge of 24 μC is placed in a uniform electric field of 610 N/C directed vertically. What is the mass of this object if it floats in the field?
For the object to float, the electric force balances gravity: qE = mg
m = qE/g = (24×10⁻⁶)(610)/9.8 = 0.01464/9.8
m ≈ 1.49 × 10⁻³ kg (1.49 g)
| Session | Questions |
|---|---|
| 2026 Annual | 4 |
| 2025 1st Annual | 10 |
| 2025 2nd Annual | 11 |
| 2024 Annual | 5 |
| 2023 Annual | 4 |
34 real Federal Board (FBISE) Physics questions on Electrostatics from 2023 to 2026, for 11th and 12th class. Each one shows the session it came from.
No. We could not find an official FBISE marking scheme for these papers, so the answers and explanations are written by Tayyari Karo for practice. Check anything important with your teacher or textbook.
You can start free with no signup. A small set of papers per subject is free, and Premium unlocks the full question bank.