Practise 30 real Federal Board questions on Motion and Force from 2023 to 2026. See the answer and explanation as soon as you answer.
Motion and Force is one of the 14 main chapters in our Federal Board FSC Physics question bank (11th and 12th class), and about 6% of its real questions come from it. Tayyari Karo has 30 real questions on this chapter from 2023 to 2026; 12 are multiple choice and marked instantly, and the rest are short and long questions with a model answer. By difficulty: 21 medium, 7 easy, 2 hard.
Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.
These are real past-paper questions. Think of your answer first, then open the explanation.
Which of the following equations is dimensionally correct?
Answer: A. v_f = v_i + at
v_f=v_i+at is dimensionally consistent (all terms are velocity). In B, 2at has units of velocity not velocity² (should be 2as); in C, the missing power on t makes the second term have the wrong dimension (should be at²); in D, ma² has units of force×acceleration, not force.
Time of flight of a projectile depends on:
Answer: C. Vertical component of velocity
Time of flight T = 2v sinθ/g depends only on the vertical component of the initial velocity (v sinθ) and g.
The unit of force in terms of base units is:
Answer: B. kg·m/s²
Force = mass × acceleration, so its SI base units are kg·m/s² (the newton).
For a freely falling body, the vertical velocity at the 4th second is:
Answer: D. 39.2 ms⁻¹
v = gt = 9.8 × 4 = 39.2 m/s (starting from rest).
The maximum range of a projectile is obtained when launch angle θ =
Answer: B. 45°
Range R = v²sin2θ/g is maximum when sin2θ = 1, i.e. θ = 45°.
Angle of projection, for which the range of a projectile becomes half of its maximum range, is equal to:
Answer: D. 15°
R = (v²/g)sin2θ; max range at θ=45°. Half range needs sin2θ=0.5 ⇒ 2θ=30° ⇒ θ=15° (or 75°, not listed).
A 5 kg shell is fired with a muzzle velocity of 700 ms⁻¹ from a gun barrel 2.4 m long. Calculate the average value of: (a) the acceleration, (b) the time to come out of the barrel.
(a) Using v² = u² + 2as, with u = 0 (starts at rest in the barrel), v = 700 m/s, s = 2.4 m:
a = v²/(2s) = 700²/(2×2.4) = 490000/4.8
a ≈ 1.02 × 10⁵ m/s²
(b) Using v = u + at: t = v/a = 700/(1.02×10⁵)
t ≈ 6.86 × 10⁻³ s
For a projectile show that: R = R_max sin2θ.
Range of a projectile launched with speed v at angle θ: R = (v²sin2θ)/g.
Maximum range occurs at θ=45° (sin2θ=1): R_max = v²/g.
So v²/g = R_max, and substituting back: R = R_max sin2θ — the range at any angle θ equals the maximum range multiplied by sin2θ.
| Session | Questions |
|---|---|
| 2026 Annual | 5 |
| 2025 1st Annual | 2 |
| 2025 2nd Annual | 9 |
| 2024 Annual | 8 |
| 2023 Annual | 6 |
30 real Federal Board (FBISE) Physics questions on Motion and Force from 2023 to 2026, for 11th and 12th class. Each one shows the session it came from.
No. We could not find an official FBISE marking scheme for these papers, so the answers and explanations are written by Tayyari Karo for practice. Check anything important with your teacher or textbook.
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