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A Level Chemistry: Electrochemistry, questions with answers

Practise 17 real questions on Electrochemistry from 2021 to 2026. See the answer and explanation as soon as you answer.

17real questions
8multiple choice
7exam sessions

About Electrochemistry in A Level Chemistry

Electrochemistry is one of the 18 main topics in our A Level Chemistry (Cambridge (CAIE) 9701) question bank, and about 3% of its real questions come from it. Tayyari Karo has 17 real questions on this topic from 2021 to 2026, from Paper 1, Paper 4; 8 are multiple choice and marked instantly, and the rest are structured questions with a model answer. By difficulty: 14 hard, 3 medium.

Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.

Try 6 real questions

These are real past-paper questions. Think of your answer first, then open the explanation.

October/November 2025 · Paper 1 · Electrochemistry

Sulfite ions react separately with zinc and with manganese dioxide: aSO3²⁻(aq) + bH2O(l) + Zn(s) → Zn²⁺(aq) + cOH⁻(aq) + dS2O4²⁻(aq); MnO2(s) + wSO3²⁻(aq) + xH⁺(aq) → Mn²⁺(aq) + yS2O6²⁻(aq) + zH2O(l). Which numbers are correct for a, b, w and x?

  1. a=1, b=2, w=2, x=4
  2. a=2, b=2, w=2, x=4
  3. a=1, b=2, w=4, x=2
  4. a=2, b=2, w=4, x=2
Show answer and explanation

Answer: B. a=2, b=2, w=2, x=4

Balancing charge and atoms for both half-reactions gives a=2, b=2, w=2, x=4.

October/November 2025 · Paper 1 · Electrochemistry

Which equation shows hydrogen acting as an oxidising agent?

  1. H2 + 2K → 2K⁺H⁻
  2. H2 + I2 → 2HI
  3. H2 + Cu2S + ZnO → 2Cu + ZnS + H2O
  4. 3H2 + N2 → 2NH3
Show answer and explanation

Answer: A. H2 + 2K → 2K⁺H⁻

In K⁺H⁻, hydrogen is reduced from 0 to −1 (gains electrons), so H2 is the oxidising agent.

October/November 2025 · Paper 1 · Electrochemistry

Photochromic glass darkens due to silver atoms. Reaction 1: Ag⁺ + Cl⁻ ⇌ Ag + Cl. Reaction 2: Cu⁺ + Cl → Cu²⁺ + Cl⁻. Reaction 3: Cu²⁺ + Ag → Cu⁺ + Ag⁺. Which statement about these reactions is correct?

  1. Cu⁺ and Cu²⁺ ions act as catalysts.
  2. Cu⁺ ions act as an oxidising agent in reaction 2.
  3. Reaction 3 increases the darkness of the glass.
  4. Silver atoms are reduced in reaction 3.
Show answer and explanation

Answer: A. Cu⁺ and Cu²⁺ ions act as catalysts.

Cu⁺/Cu²⁺ are regenerated over the cycle (reaction 2 then reaction 3), so overall they act as a catalyst for converting Cl back to Cl⁻, reforming Ag⁺.

May/June 2024 · Paper 1 · Electrochemistry

Oxygen can be prepared by the reaction of potassium manganate(VII), KMnO4, hydrogen peroxide, H2O2, and sulfuric acid, H2SO4. Each H2O2 molecule loses two electrons in this reaction, and the other products are potassium sulfate, manganese(II) sulfate and water. How many moles of oxygen gas are produced when 1.0 mol of KMnO4 reacts with an excess of H2O2 in acidic conditions?

  1. 2.0 mol
  2. 2.5 mol
  3. 4.5 mol
  4. 5.0 mol
Show answer and explanation

Answer: B. 2.5 mol

MnO4⁻ + 8H⁺ + 5e⁻ → Mn²⁺ + 4H2O needs 5 mol electrons per mol MnO4⁻; since each H2O2 supplies 2 electrons (H2O2 → O2 + 2H⁺ + 2e⁻), 2.5 mol H2O2 react, producing 2.5 mol O2.

October/November 2024 · Paper 1 · Electrochemistry

In alkaline solution, MnO4− ions oxidise SO32− ions to SO42− ions. The MnO4− ions are reduced to MnO2. What is the ratio of the two ions (MnO4− : SO32−) in the balanced chemical equation for this reaction?

  1. 2 : 3
  2. 3 : 2
  3. 4 : 7
  4. 7 : 4
Show answer and explanation

Answer: A. 2 : 3

Mn goes from +7 to +4 (gain of 3e−); S goes from +4 to +6 (loss of 2e−). Balancing electrons: 2MnO4− (6e− gained) with 3SO32− (6e− lost) gives a 2:3 ratio.

October/November 2022 · Paper 1 · Electrochemistry

Sodium dichromate(VI), Na2Cr2O7, reacts with hydrogen peroxide, H2O2, producing Cr3+ ions, water and oxygen. What is the correctly balanced ionic equation for this reaction?

  1. Cr2O7²⁻ + 2H+ + H2O2 → 2Cr3+ + 2H2O + 4O2
  2. Cr2O7²⁻ + 8H+ + 3H2O2 → 2Cr3+ + 7H2O + 3O2
  3. Cr2O7²⁻ + 8H+ + 6H2O2 → 2Cr3+ + 10H2O + 6O2
  4. Cr2O7²⁻ + 14H+ + 3H2O2 → 2Cr3+ + 7H2O + 3O2
Show answer and explanation

Answer: B. Cr2O7²⁻ + 8H+ + 3H2O2 → 2Cr3+ + 7H2O + 3O2

Balancing charge, atoms and electrons for the Cr2O7²⁻/Cr3+ (6e⁻, 14H+ half-equation combined with 3 × H2O2 → O2 + 2H+ + 2e⁻) gives Cr2O7²⁻ + 8H+ + 3H2O2 → 2Cr3+ + 7H2O + 3O2.

Sessions with Electrochemistry questions

SessionPaper 1Paper 4
May/June 2026–1
October/November 202531
May/June 202421
October/November 20241–
October/November 202211
May/June 202113
October/November 2021–2

Common questions

What does the Electrochemistry topic cover on this page?

17 real A Level Chemistry (9701) questions on Electrochemistry from 2021 to 2026, from Paper 1, Paper 4. Each one shows the year, session and paper it came from.

Do I get the answers and explanations?

Yes. Every question shows the correct answer and a short explanation the moment you answer.

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