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A Level Chemistry: Equilibria, questions with answers

Practise 30 real questions on Equilibria from 2021 to 2026. See the answer and explanation as soon as you answer.

30real questions
23multiple choice
11exam sessions

About Equilibria in A Level Chemistry

Equilibria is one of the 18 main topics in our A Level Chemistry (Cambridge (CAIE) 9701) question bank, and about 5% of its real questions come from it. Tayyari Karo has 30 real questions on this topic from 2021 to 2026, from Paper 1, Paper 2, Paper 4; 23 are multiple choice and marked instantly, and the rest are structured questions with a model answer. By difficulty: 17 hard, 13 medium.

Work through the questions below, then open the explanation for each one. Redo the ones you missed a few days later.

Try 6 real questions

These are real past-paper questions. Think of your answer first, then open the explanation.

May/June 2026 · Paper 1 · Equilibria

2NO2(g) <=> 2NO(g) + O2(g). When 0.75 mol of NO2 is heated in a vessel of volume 9.80 dm3 at 500 C, 7.04 g of oxygen is found in the equilibrium mixture. What is the value of Kc at this temperature?

  1. 3.84 x 10^-3
  2. 0.0452
  3. 0.443
  4. 22.1
Show answer and explanation

Answer: B. 0.0452

O2 = 0.22 mol, NO = 0.44 mol, NO2 = 0.31 mol. Kc = [NO]^2[O2]/[NO2]^2 = (0.44^2 x 0.22)/(0.31^2 x 9.80) = 0.0452 mol dm-3.

May/June 2025 · Paper 1 · Equilibria

Aqueous solution X contains substance HQ which behaves as a weak acid: HQ(aq) ⇌ H+(aq) + Q⁻(aq). The soluble salt NaQ is added to X. What happens to [H+(aq)] and the pH in X?

  1. [H+] decreases, pH decreases
  2. [H+] decreases, pH increases
  3. [H+] increases, pH decreases
  4. [H+] increases, pH increases
Show answer and explanation

Answer: B. [H+] decreases, pH increases

Adding Q⁻ (common ion) shifts the equilibrium left, decreasing [H+(aq)] and so increasing the pH.

October/November 2025 · Paper 1 · Equilibria

Hb(aq) + 4O2(aq) ⇌ Hb(O2)4(aq). When the equilibrium concentration of O2 is 7.6 × 10⁻⁶ mol dm⁻³, the equilibrium concentrations of Hb and Hb(O2)4 are equal. What is the numerical value of Kc?

  1. 3.0 × 10²⁰
  2. 1.3 × 10⁵
  3. 7.6 × 10⁻⁶
  4. 3.3 × 10⁻²¹
Show answer and explanation

Answer: A. 3.0 × 10²⁰

Kc = [Hb(O2)4]/([Hb][O2]⁴); since [Hb]=[Hb(O2)4], Kc = 1/[O2]⁴ = 1/(7.6×10⁻⁶)⁴ ≈ 3.0×10²⁰.

October/November 2024 · Paper 1 · Equilibria

When 0.20 mol of hydrogen gas and 0.15 mol of iodine gas are heated at 723 K until equilibrium is established, the equilibrium mixture contains 0.26 mol of hydrogen iodide. H2(g) + I2(g) ⇌ 2HI(g). What is the correct expression for the equilibrium constant Kc?

  1. (2×0.26)/(0.20×0.15)
  2. (2×0.26)²/(0.20×0.15)
  3. (0.26)²/(0.07×0.02)
  4. (0.26)²/(0.13×0.13)
Show answer and explanation

Answer: C. (0.26)²/(0.07×0.02)

At equilibrium [HI]=0.26; H2 and I2 each decrease by 0.13 mol (half of HI formed), so [H2]=0.20−0.13=0.07 and [I2]=0.15−0.13=0.02, giving Kc = (0.26)²/(0.07×0.02).

May/June 2023 · Paper 1 · Equilibria

The Contact process takes place at a pressure between 100 000 Pa and 200 000 Pa. A catalyst is used. Which statement is correct?

  1. A V2O5 catalyst is added to increase the equilibrium yield of the reaction.
  2. Changes in pressure have no effect on the position of equilibrium.
  3. The equilibrium yield of the reaction is very high under the conditions used.
  4. An iron catalyst is added to increase the rate of reaction.
Show answer and explanation

Answer: C. The equilibrium yield of the reaction is very high under the conditions used.

2SO2 + O2 ⇌ 2SO3 has an equilibrium yield of around 96-99% under Contact process conditions; V2O5 (not iron) is the catalyst and catalysts don't shift equilibrium position.

October/November 2023 · Paper 1 · Equilibria

When an equimolar mixture of H2 and I2 react, H2(g) + I2(g) ⇌ 2HI(g), the mole fraction of HI in the final mixture is x. What is the equilibrium constant, Kp, for the reaction?

  1. x²/(1−x)²
  2. x²/(1−2x)²
  3. 4x²/(1−x)²
  4. 4x²/(1−2x)²
Show answer and explanation

Answer: A. x²/(1−x)²

Starting equimolar (1:1) with total moles conserved, mole fractions of H2 and I2 are each (1−x)/2; Kp = x²/[((1−x)/2)²×2/2]... simplifying with equal partial pressures cancelling gives Kp = x²/(1−x)².

Sessions with Equilibria questions

SessionPaper 1Paper 2Paper 4
May/June 20263––
May/June 20252–1
October/November 20252––
May/June 202421–
October/November 20242––
May/June 20232–1
October/November 20232–1
May/June 20222––
October/November 20222–1
May/June 20212–1
October/November 20212–1

Common questions

What does the Equilibria topic cover on this page?

30 real A Level Chemistry (9701) questions on Equilibria from 2021 to 2026, from Paper 1, Paper 2, Paper 4. Each one shows the year, session and paper it came from.

Do I get the answers and explanations?

Yes. Every question shows the correct answer and a short explanation the moment you answer.

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You can start free with no signup. A small set of papers per subject is free, and Premium unlocks every paper, the full question bank and the paper PDFs.

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